The volume, in mL, of 0.02 M K2Cr2O7 — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

milliequivalent of K2Cr2O7 = milliequivalent of FeC2O4 Vml × 0.02 × 6 = 3 288 .   Vml × 0.02 × 6 = 2 × 6 Vml = 100 ml | JEE MAIN-2020 | DATE : 05-09-2020 (SHIFT-2) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 10