The volume, in mL, of 0.02 M K2Cr2O7 — JEE Mains Chemistry Past Papers Chemistry Question
Question
The volume, in mL, of 0.02 M K2Cr2O7
Answer: 100
💡 Solution & Explanation
milliequivalent of K2Cr2O7 = milliequivalent of FeC2O4 Vml × 0.02 × 6 = 3 288 . Vml × 0.02 × 6 = 2 × 6 Vml = 100 ml | JEE MAIN-2020 | DATE : 05-09-2020 (SHIFT-2) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 10
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