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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: B

💡 Solution & Explanation

2 P CO K P  … (1)   2 2 CO P CO P K P  … (2) Multiply Eq. (1) and (2), we get   2 P P CO K .K P  2 1 CO P P P K .K 4 10

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