The hybridization of P exhibited in PF is sp d . The value of y is _____ 5 x y — Chemical Bonding Chemistry Question

💡 Solution & Explanation

# Solution: Finding y in PF₅ Hybridization **Step 1: Identify the hybridization type** PF₅ exhibits sp³d hybridization (not sp d^y as written in the question format). **Step 2: Understand sp³d notation** The notation sp^x d^y means: - s orbital: 1 orbital (exponent = 1) - p orbitals: 3 orbitals (exponent = 3) - d orbitals: 1 orbital (exponent = y) **Step 3: Determine orbital requirements** Phosphorus in PF₅ forms 5 bonds with 5 fluorine atoms, requiring 5 hybrid orbitals. **Step 4: Apply hybridization formula** Total hybrid orbitals = number of s + p + d orbitals used 5 = 1 + 3 + y **Step 5: Solve for y** y = 5 - 1 - 3 = 1 The hybridization is sp³d¹, where one d orbital is used to accommodate the 5 bonding pairs. Therefore, the answer is **1.00**.