What is the angular speed of an electron revolving in the third orbit of He^+ ion? — Atomic Structure Chemistry Question

💡 Solution & Explanation

Angular speed ω is given by ω = v / r. For He^+ (Z = 2) in the third orbit (n = 3): speed v = 2.188 * 10^6 * Z / n = 2.188 * 10^6 * 2 / 3 = 1.459 * 10^6 m/s. Radius r = 0.529 * 10^-10 * n^2 / Z = 0.529 * 10^-10 * 9 / 2 = 2.3805 * 10^-10 m. Calculating ω = (1.459 * 10^6) / (2.3805 * 10^-10) = 6.129 * 10^15 s^-1, which matches option (a).