See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(for Q.35 and 36) C H3 C Br H CH2 Br 2 2 3 2 NaNH NaNH 3 3 2 3 2 equivalent CH CH I CH C CH CH C C CH CH          3 Li Liq. NH  C C C H3 H CH2CH3 H  A 3 2 O ,H O,Zn C O C H3 H   B  C C O CH2CH3 H From 1 mol 1,2-dibromo propane to pent-2-yne 3 mol 2 NaNH is needed. AITS-FT-VII (Paper-2)-PCM(Sol.)-JEE(Advanced)/22 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 8 C O C H3 H 1 mol 44 g  