Following five solutions of were prepared as: first, 0.1 mole in 1 L; second, 0.2 mole in 2 L; third β Ionic Equilibrium Chemistry Question
Question
Following five solutions of $KOH$ were prepared as: first, 0.1 mole in 1 L; second, 0.2 mole in 2 L; third, 0.3 mole in 3 L; fourth, 0.4 mole in 4 L; fifth, 0.5 mole in 5 L. The pH of resultant solution, when all these solutions are mixed, is
Answer: C
π‘ Solution & Explanation
Each solution has the same concentration: 0.1 M $KOH$. Mixing identical concentrations gives the same concentration: [OH-] = 0.1 M. pOH = 1. pH = 13.
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