See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

3 4 2 4 2 H PO NaOH NaH PO H O 10 10 15 10 10      2 4 2 4 2 NaH PO NaOH Na HPO H O 10 5 5 5 5      Resulting solution is buffer, a S pH pK log 8 A   