A2(g) - 2A(g): K1 = e^(-14000/RT) + 5; B3(g) - 3B(g): K2 = e^(-20000/RT) + 10. 1 mol each in 100 L flask. Reactions start at same rate. Incorrect information:

Question

A2(g) -> 2A(g): K1 = e^(-14000/RT) + 5; B3(g) -> 3B(g): K2 = e^(-20000/RT) + 10. 1 mol each in 100 L flask. Reactions start at same rate. Incorrect information:

Prashant Kotian · Accepted Answer

Correct answer: C. K1 = K2: e^(-14000/RT)+5 = e^(-20000/RT)+10 => RT=1200 => T=1200/8.314 K (A correct). K1=K2 => [A2]=[B3] always => P_A2/P_B3=1 (B correct). Initial P = nRT/V is large (~24 atm), so total pressure never < 0.2 atm (C incorrect). P_A/P_B depends on stoichiometry: at equal depletion rates, P_A = 2*(A2 decomposed) and P_B = 3*(B3 decomposed), ratio ≠ 1 (D incorrect per book). Book marks C as the incorrect information.

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