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Consider the following electromagnetic waves Wavelength of A = 400nm Frequency of B = 1016 sec-1 WavAITS & Test Series Chemistry Question

Question

Consider the following electromagnetic waves Wavelength of A = 400nm Frequency of B = 1016 sec-1 Wave number of C = 104 cm-1 Order of energies is: A) A > B > C B) B > A > C C) B > C > A D) C > A > B

Answer: B
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