See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Sinc   4 M aq  and     2 6 M OH aq      ions are present in the solution.                   2 4 6 S M aq M OH aq 2 sp c 4 K S K OH OH              For minimum solubility dS 0 d OH      5 sp c 4.K OH 2K OH 0                                6 sp c OH 4K OH 2K 0 Since, OH 0      6 sp c 4K OH 2K 0          Yashpatil TG~ @bohring_bot For More Material Join: @JEEAdvanced_2024 Rankers Academy JEE AITS-PT-I-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 10 6 c sp K OH 2K         1 1 2 6 6 c 20 sp K 2 10 OH 2K 2 10                                   3 OH 10 pOH 3           pH 14 3 11    