An electron revolving round H-nucleus in ground state absorbs 10.2 eV energy. Its angular momentum i — Atomic Structure Chemistry Question

💡 Solution & Explanation

Absorbing 10.2 eV of energy drives a transition from the ground state (n_1 = 1, E_1 = -13.6 eV) to the first excited state (n_2 = 2, E_2 = -3.4 eV). The change in angular momentum is Δ L = L_2 - L_1 = 2 * h / (2*π) - 1 * h / (2*π) = h / (2*π).