2AgF + MgCl2 -> MgF2↓ + 2AgCl↓ — Redox Reactions and Volumetric Analysis Chemistry Question
Question
2AgF + MgCl2 -> MgF2↓ + 2AgCl↓
Answer: A
💡 Solution & Explanation
Step 1: Identify starting materials: Silver fluoride (AgF) is uniquely soluble among silver halides, and magnesium chloride (MgCl2) is also highly soluble in water. Step 2: Analyze the products: When these clear solutions are mixed, double displacement occurs to yield two highly insoluble compounds: magnesium fluoride (MgF2↓) and silver chloride (AgCl↓). Step 3: Since solid precipitates are formed from the mixing of two soluble solutions, this is classified as a precipitate formation reaction (type A).
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes