JEE Mains Chemistry Past PapershardNUMERICAL

The following data was obtained for chemical reaction given below at 975 K. 2NO(g) + 2H2(g) N2(g) + JEE Mains Chemistry Past Papers Chemistry Question

Question

The following data was obtained for chemical reaction given below at 975 K. 2NO(g) + 2H2(g) N2(g) + 2H2O(g) [NO] [H2] Rate mol L–1 mol L–1 mol L–1 s–1 (A) 8 × 10–5 8 × 10–5 7 × 10–9 (B) 24 × 10–5 8 × 10–5 2.1 × 10–8 (C) 24 × 10–5 32 × 10–5 8.4 × 10–8 The order of the reaction with respect to NO is………… [Integer answer] uhps nh x;h jklk;fud vfHkfØ;k ds fy, 975 K ij fuEufyf[kr vk¡dM+s izkIr gq, : 2NO(g) + 2H2(g) N2(g) + 2H2O(g) [NO] [H2] nj mol L–1 mol L–1 mol L–1 s–1 (A) 8 × 10–5 8 × 10–5 7 × 10–9 (B) 24 × 10–5 8 × 10–5 2.1 × 10–8 (C) 24 × 10–5 32 × 10–5 8.4 × 10–8 NO ds izfr vfHkfØ;k dh dksfV gSa………… [fudVre iw.kkZd esa]

Answer: .

💡 Solution & Explanation

rate = K[NO]x [H2]y From (A) 7 × 10–9 = K(8 × 10–5)x (8 × 10–5)y …………. (1) From (B) 2.1 × 10–8 = K(24 × 10–5)x (8 × 10–5)y …………. (2) (1)/(2)  9 1 . 10     = y x y x ) 8 ( ) 24 ( K ) 8 ( ) 8 ( K               1 = x 1        x = 1 Order of reaction w.r.t. NO is x = 1. | JEE MAIN-2021 | DATE : 26-08-2021 (SHIFT-1) | PAPER-1 | OFFICIAL PAPER | CHEMISTRY PAGE # 11

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