2.5 g of a non-volatile, non-electrolyte is dis — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

ute concentration in negligible with respect to the solvent concentration, the vapour pressure of the resulting aqueous solution is _______ mm of Hg (nearest integer) [Given : Molal boiling point elevation constant of water (Kb) = 0.52 K. kg mol–1, 1 atm pressure = 760 mm of Hg, molar mass of water = 18 g mol–1] Ans. (707) Sol. 2 = 0.52 × m m 0.52  According to question, solution is much diluted so solute o solvent n P P n   solvent o P m M P    o solvent m P P M    0.52 18    = 52.615 P5 = 760 – 52.615 = 707.385 mm of Hg