See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

In position 1 Stored energy = 2 2 1 ) ( 2 1 e e C  In position 2 Stored energy = 2 1 2 1 Ce C e1 e2 1 2 Extra energy drawn from the battery = e1 q where q is the additional charge drawn from the battery. Now q = e1C – (e1 – e2) C = e2C  Extra energy drawn from the battery = e1 (e2C) = e1e2C Heat produced = loss in stored battery + extra energy drawn from the battery = C e e C e C e e 2 1 2 1 2 2 1 2 1 ) ( 2 1    = C e C e e C e C e C e e C e 2 2 2 1 2 1 2 2 2 1 2 1 2 1 2 1 2 1 2 1          2 10 μF 2 2 1 100 J For More Material Join: @JEEAdvanced_2024 AITS-CRT-II-PCM(Sol.)-JEE(Main)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 6