The enthalpy change involved in the oxidation of glucose is -2880 kJ/mol. Twenty five per cent of th β Thermodynamics and Thermochemistry Chemistry Question
Question
The enthalpy change involved in the oxidation of glucose is -2880 kJ/mol. Twenty five per cent of this energy is available for muscular work. If 100 kJ of muscular work is needed to walk 1 km, what is the maximum distance that a person will be able to walk after eating 120 g of glucose?
Answer: D
π‘ Solution & Explanation
Molar mass of glucose = 180 g/mol. Moles of glucose in 120 g: n = 120 / 180 = 2/3 mol. Total energy from 120 g: E_total = (2/3 mol) * 2880 kJ/mol = 1920 kJ. Energy available for muscular work: E_work = 25% of 1920 kJ = 480 kJ. Since 100 kJ is needed per km, the maximum distance is: d = 480 kJ / 100 kJ/km = 4.8 km.
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