For hydrogen atom, the number of revolutions of the electron per second in the orbit of quantum numb — Atomic Structure Chemistry Question

💡 Solution & Explanation

The number of revolutions per second represents the frequency of revolution f = v / (2*π*r). Since velocity v is ∝ 1/n and radius r is ∝ n^2, the frequency f is ∝ (1/n) / n^2 = 1/n^3 = n^-3.