See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  2 2 3 2 CaCl 5 ClO Ca CaOCl 6    HCl 2 SO Na SO H NaCl 2 4 2 4 2     2 2 3 2 2 SO S O H NaCl 2 HCl 2 O S Na         a = 1, b = 5, c = 2, d = 2, e = 2 (a + b + c) – (d + e) = (1 + 5 + 2) – (2 + 2) = 4 For More Material Join: @JEEAdvanced_2024 AITS-CRT-IV (Paper-2)-PCM(Sol.)-JEE(Advanced)/2023 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 11