A quantity of 4 ml of a gas at 1 atm and 300 K is dissolved in 1 L of water. The volume (in ml) of gas that will dissolve in 0.5 L of water at 4 atm and 300 K, is

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Question

Prashant Kotian · Accepted Answer

Correct answer: 0002. Moles dissolved ∝ P × V_solvent → n₂/n₁ = (4 × 0.5)/(1 × 1) = 2. V_gas = nRT/P → V₂ = 2n₁RT/4 = 0.5 × 4 ml = 2 ml.

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