A chloro compound "A". (i) forms aldehydes on ozonolysis followed by the hydrolysis. (ii) when vaporized completely 1.53 g of A, gives 448 mL of vapour at STP. The number of carbon atoms in a molecule

Question

A chloro compound "A". (i) forms aldehydes on ozonolysis followed by the hydrolysis. (ii) when vaporized completely 1.53 g of A, gives 448 mL of vapour at STP. The number of carbon atoms in a molecule of compound A is _______.

Prashant Kotian · Accepted Answer

Correct answer: 3.00. **Step 1: Find the molar mass of compound A** Using the ideal gas law at STP: - Volume = 448 mL = 0.448 L - Molar volume at STP = 22.4 L/mol - Moles of A = 0.448/22.4 = 0.02 mol - Mass = 1.53 g Molar mass = mass/moles = 1.53/0.02 = **76.5 g/mol ≈ 76 g/mol** **Step 2: Determine the molecular formula** Since A is a chloro compound that forms aldehydes on ozonolysis, it contains a C=C double bond. Let the molecular formula be CₙH₂ₙCl (alkene with one Cl substituent) Molar mass equation: 12n + 2n + 35.5 = 76 14n + 35.5 = 76 14n = 40.5 n = **2.89 ≈ 3** **Step 3: Verify the molecular formula** For C₃H₆Cl: - Molar mass = (3 × 12) + (6 × 1) + 35.5 = 36 + 6 + 35.5 = 77.5 g/mol ✓ (close to 76) **Step 4: Confirm with ozonolysis** A C₃ alkene with chloro substituent (like ClCH₂-CH=CH₂) produces aldehydes upon ozonolysis, consistent with the given information. Therefore, the answer is **3.00**.

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