Dilute nitric acid on reaction with silver liberates : — d and f Block Elements Chemistry Question

💡 Solution & Explanation

Step 1: Nitric acid reacts with metals differently depending on its concentration and the reactivity of the metal. Step 2: When silver (a relatively unreactive metal) is treated with dilute nitric acid (HNO3), it is oxidized to silver nitrate, and the nitric acid is reduced to nitric oxide (NO) gas. Step 3: The balanced chemical equation is: 3Ag + 4HNO3 (dilute) -> 3AgNO3 + NO + 2H2O. Therefore, the liberated gas is NO, corresponding to option (a).