25 mL of silver nitrate solution (1M) is added dropwise to 25 mL of potassium iodide (1.05 M) soluti — JEE Mains Chemistry Past Papers Chemistry Question
Question
25 mL of silver nitrate solution (1M) is added dropwise to 25 mL of potassium iodide (1.05 M) solution. The ion(s) present in very small quantity in the solution is/are (A) Ag+ and I– both (B) – only (C) K+ only (D) NO3– only
Answer: A
💡 Solution & Explanation
AgNO3 = 25 millmole KI = 26.25 millmole AgNO3 + KI AgI + KNO3 so most of the Ag+ + KNO3 precipitated as AgI (sparingly soluble salt) so ion remaining in small quantities are Ag+ and I–.
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes