Ionization energy of an element is : — Periodic Table and Periodicity Chemistry Question

💡 Solution & Explanation

Step 1: Identify the element with the given configuration. The atomic number is 36 (Kr) + 10 (4d) + 14 (4f) + 2 (5s) + 6 (5p) + 2 (6s) = 70, which is Ytterbium (Yb). Step 2: Ytterbium is a lanthanide element. The last electron entered and completed the 4f subshell (4f14). Step 3: Elements in which the f-orbitals are being filled belong to the f-block, so the correct option is (d).