AB, A2 and B2 are diatomic molecules. If the bond enthalpies of A2, AB and B2 are in the ratio 2:2:1 — Thermodynamics and Thermochemistry Chemistry Question
Question
AB, A2 and B2 are diatomic molecules. If the bond enthalpies of A2, AB and B2 are in the ratio 2:2:1 and enthalpy of formation AB from A2 and B2 is -100 kJ mole^-1. What is the bond energy of A2?
Answer: D
💡 Solution & Explanation
1/2 A2 + 1/2 B2 -> AB; dH = -100. Let BE(B2) = x, BE(A2) = 2x, BE(AB) = 2x. -100 = 0.5*(2x) + 0.5*x - 2x = -0.5x. x = 200. BE(A2) = 2x = 400 kJ/mol.
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