α-maltose hydrolysis: C12H22O11(aq) + (l) - 2C6H12O6(aq). delta_f H° (kJ/mol): maltose=-2238, glucose=-1263, =-285. Kinetic data: 0.4M at 0 min; 0.1M at 50 min; 0.025M at 100 min. Correct statements:

Question

α-maltose hydrolysis: C12H22O11(aq) + $H_2O$(l) -> 2C6H12O6(aq). delta_f H° (kJ/mol): maltose=-2238, glucose=-1263, $H_2O$=-285. Kinetic data: 0.4M at 0 min; 0.1M at 50 min; 0.025M at 100 min. Correct statements:

Prashant Kotian · Accepted Answer

Correct answer: A,B,C,D. δ H_hyd = 2*(-1263) - (-2238 - 285) = -3 kJ (exothermic, A). Exothermic => Q_comb(maltose) > 2*Q_comb(glucose) (B). Exothermic => Le Chatelier: increased T shifts backward, decreasing hydrolysis (C). Conc halves every 25 min (constant t_1/2 = 25 min) => first-order (D). All correct.

💡 Solution & Explanation

Practice 22,000+ questions like this