At 298 K, the mole percentage of N2(g) in air is 80%. Water is in equilibrium with air at a pressure of 10 atm. What is the mole fraction of N2(g) in water at 298 K ? (KH for N2 is 6.5 × 10 7 mm Hg )

Question

(A) 1.23 × 10 –7
(B) 1.17 × 10 –4
(C) 9.35 × 10
(D) 9.35 × 10 –5

Prashant Kotian · Accepted Answer

Correct answer: D. 2 N H N P K .X  N P = 0.8 × 10 = 8 atm  8 × 760 = 6.5 × 10 7 × N X    N 8 760 X 6.5 10 N X = 9.35 × 10 –5.

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