See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

  3 2 2 4 2 4 2 4 3 K SO .Al SO .24H O 2K 2Al 4SO n factor = 8 1 mole 2 mol 2 mol 4 mole 8 gm eq 2 gm eq 6 gm eq 8 gm       eq 1 gm eq 1 gm eq cations 1 gm eq