There are some arrangements of atomic orbitals which are given below :
[SEE DIAGRAM]
Then calculate the value of "" where, P, Q and R are no. of arrangements which give bonding molecular orbital

Question

There are some arrangements of atomic orbitals which are given below :
[SEE DIAGRAM]
Then calculate the value of "$Q imes R - P$" where, P, Q and R are no. of arrangements which give bonding molecular orbitals (positive overlap), antibonding molecular orbitals (negative overlap) and non-bonding molecular orbitals (zero overlap) respectively.

Prashant Kotian · Accepted Answer

Correct answer: 2

**SOLUTION:** (P) = (I), (III), (IV), (VII) (4)
(Q) = (II), (V), (IX) (3)
(R) = (VI), (VIII) (2)
THEN $Q \TIMES R - P = 3 \TIMES 2 - 4 = 2$. Step 1: The enthalpy of fusion represents the energy required to melt a solid. Stronger intermolecular forces lead to a higher melting point and higher enthalpy of fusion. Step 2: Helium is a monoatomic noble gas with the weakest London dispersion forces among all elements due to its extremely small size and extremely low polarizability. Step 3: Therefore, Helium has the lowest enthalpy of fusion among the choices, matching option (d).

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