Total number of species which has/have symmetrical electronic distribution in their HOMO and also paramagnetic.

Question

Total number of species which has/have symmetrical electronic distribution in their HOMO and also paramagnetic.
$N_2^+, O_2^{2-}, C_2, O_2, B_2, C_2^{2+}, N_2^{2-}$

Prashant Kotian · Accepted Answer

Correct answer: 4

**SOLUTION:** $N_2^+, O_2, B_2, N_2^{2-}$ HAVE SYMMETRICAL ELECTRONIC DISTRIBUTION IN THEIR HOMO AND ARE ALSO PARAMAGNETIC.. Step 1: Nitrogen dioxide (NO2) is an odd-electron bent molecule. Step 2: The central Nitrogen atom forms two sigma bonds and holds a single odd electron in a hybridized orbital. The total steric number is 3 (2 sigma bonds + 1 odd-electron domain). Step 3: A steric number of 3 corresponds to sp2 hybridization of the Nitrogen atom, which is option (b).

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