Rate law: RCl + (aq) - ROH + ; rate = K1[RCl]. The rate will be 1. Doubled on doubling . 2. Halved on halving alkyl halide. 3. Increased on increasing temperature. 4. Unaffected by temperature. Corre

Question

Rate law: RCl + $NaOH$(aq) -> ROH + $NaCl$; rate = K1[RCl]. The rate will be 1. Doubled on doubling $NaOH$. 2. Halved on halving alkyl halide. 3. Increased on increasing temperature. 4. Unaffected by temperature. Correct?

Prashant Kotian · Accepted Answer

Correct answer: D. Zero-order in : (1) doubling has no effect. First-order in RCl: (2) halving [RCl] halves rate (correct). Increasing T increases K1 and rate (3 correct). Statements 2 and 3 are correct.

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