The magnetic moment is measured in Bohr Magneton (BM). Spin only magnetic moment of Fe in [Fe(H2O)6]3+ and [Fe(CN)6]3– complexes respectively is: (A) 5.92 B.M. and 1.732 B.M. (B) 6.92 B.M. in both (C)

Question

The magnetic moment is measured in Bohr Magneton (BM). Spin only magnetic moment of Fe in [Fe(H2O)6]3+ and [Fe(CN)6]3– complexes respectively is:

(A) 5.92 B.M. and 1.732 B.M.
(B) 6.92 B.M. in both
(C) 3.87 B.M. and 1.732 B.M.
(D) 4.89 B.M. and 6.92 B.M.

Prashant Kotian · Accepted Answer

Correct answer: A. [Fe(H2O)6]+3 Oxidation number of Fe = +3 Fe+3 = 3d5 ; H2O is W.F.L so configuration is t2g1,1,1 eg1,1 Number of unpaired electron n = 5 magnetic moment (spin only) ) (   n n  B.M. so   B.M. = 5.85 B.M. [Fe(CN)6]3– Oxidation number of Fe = +3 Fe+3 = 3d5 ; CN– is S.F.L so configuration is t2g2,2,1 eg0,0 Number of unpaired electron n = 1 magnetic moment (spin only) ) (   n n  B.M. so   B.M. = 1.73 B.M. | JEE(Main) 2023 | DATE : 11-04-2023 (SHIFT-2) | PAPER-1 | CHEMISTRY PAGE # 2

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