Correct answer: 125. Kinetic energy 2 1 E mv 2   2 2 2 2 E v v 100 100 (1.5) 1 100 E v              E 100 125% E   

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 125

💡 Solution & Explanation

Kinetic energy 2 1 E mv 2   2 2 2 2 E v v 100 100 (1.5) 1 100 E v              E 100 125% E   

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