See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Solution for the Q. No. 33 and 34. 2 CO  2 red Br /P  C H3 CH CH3 CH2COOH C H3 C CH3 C H H Br C O OH  Y HBr   C CH C O OH C C C CH2 C H3 C H3 3 2 O H O/Zn  C O C H3 C H3  N  P  C H O H C O C H3 C H3  2 3 3 Cl / OH CHCl CH COO Q Salt      Molecular weight of Q = 12 + 1 + (35.5 × 3) = 119.5 Molecular weight of Y = (12 × 5) + (9 × 1) + 32 + 79.9 = 180.9 Rankers Academy JEE For More Material Join: @JEEAdvanced_2024 AITS-PT-II (Paper-2)-PCM(Sol.)-JEE(Advanced)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 16 Mathematics PART – III SECTION – A