The minimum work which must be done to compress 16 g of oxygen isothermally, at 300 K from a pressure of 1.01325 * 10^3 N/m^2 to 1.01325 * 10^5 N/m^2 is (ln100 = 4.6, R = 8.3 J/K-mol)

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Prashant Kotian · Accepted Answer

Correct answer: A. n = 16 / 32 = 0.5 mol. Minimum work of compression is reversible compression work: W = nRT ln(P2/P1) = 0.5 * 8.3 * 300 * ln(100) = 0.5 * 8.3 * 300 * 4.6 = 5727 J.

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