For hypothetical reaction: A - B takes place according to: Step I: A C (fast); Step II: A + C -(K2)- B (slow). the rate of reaction is (K1 is equilibrium constant)

Question

For hypothetical reaction: A -> B takes place according to: Step I: A <=(K1)=> C (fast); Step II: A + C -(K2)-> B (slow). the rate of reaction is (K1 is equilibrium constant)

Prashant Kotian · Accepted Answer

Correct answer: C. The slow step is the rate-determining step: rate = K2 [A] [C]. From the fast equilibrium step, K1 = [C]/[A] => [C] = K1 [A]. Substituting this into the rate equation: rate = K2 [A] (K1 [A]) = K1 K2 [A]^2.

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