Radionucleide 'P' decays into 'Q' and 'Q' decays into 'R' as: P --[t_1/2=1000 hrs]-- Q --[t_1/2=10 min]-- R. Number of nuclei of Q and R after 1000 hrs, if we start with 2 moles of P, are [N_A = 6 ×

Question

Radionucleide 'P' decays into 'Q' and 'Q' decays into 'R' as: P --[t_1/2=1000 hrs]--> Q --[t_1/2=10 min]--> R. Number of nuclei of Q and R after 1000 hrs, if we start with 2 moles of P, are [N_A = 6 × 10^23]

Prashant Kotian · Accepted Answer

Correct answer: BC. For Q using steady state concept Rate of appearance of Q = rate of disappearance of Q K1[P] = K2[Q] Number of nuclei of Q =      23 20 1 2 k 10 / 60 no. of nuclei of P 6 10 10 k 1000 For R, since rate constant is very high for second step than first step Number of nuclei of R = Number of nuclei of P disintegrated = 6 × 1023

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