See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

For Q using steady state concept Rate of appearance of Q = rate of disappearance of Q K1[P] = K2[Q] Number of nuclei of Q =      23 20 1 2 k 10 / 60 no. of nuclei of P 6 10 10 k 1000 For R, since rate constant is very high for second step than first step Number of nuclei of R = Number of nuclei of P disintegrated = 6 × 1023