See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Lvap = 540 cal/g Lfusion = 80 cal/g In steady state,           1 400 0 P K A x And           2 400 100 P K A 10x x Also,     1 ice fusion d P M L dt and     2 w vap d P M L dt    ice 1 fusion dM P L dt and   w 2 vap dM P L dt Now,  ice w dM dM dt dt Hence, solving, we get  = 9.