See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

To prevent 20 ml, amount of ‘X’ = 2000 mg To prevent 10 ml, amount of ‘X’ = 1000 mg To prevent from 1 ml, 10% NaCl, Amount of ‘X’ 1000 250 2 2    = Gold number For More Material Join: @JEEAdvanced_2024 Rankers Academy JEE AITS-PT-III (Paper-1)-PCM(Sol.)-JEE(Advanced)/2024 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9