With what velocity should an α-particle travel towards the nucleus of a copper atom so as to arrive at a distance 10^-13 m from the nucleus of the copper atom? (4.8 * √(29 * 60) = 200, N_A = 6 * 10^23

Question

With what velocity should an α-particle travel towards the nucleus of a copper atom so as to arrive at a distance 10^-13 m from the nucleus of the copper atom? (4.8 * √(29 * 60) = 200, N_A = 6 * 10^23)

Prashant Kotian · Accepted Answer

Correct answer: D. At closest approach: 0.5*m*v^2 = k*q1*q2/r. With q1=2e, q2=29e, r=10^-13 m, m=6.64*10^-27 kg, solving gives v = 2*10^7 m/s.

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