Correct answer: 3. 1 2 1 2 1 2 1 2 1 2 2 4 2 6 3 a a a k E k E E E E E E k k        3 x 

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AITS & Test SerieshardNUMERICAL

Question

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Answer: 3

💡 Solution & Explanation

1 2 1 2 1 2 1 2 1 2 2 4 2 6 3 a a a k E k E E E E E E k k        3 x 

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