An ideal gas, V C R , is expanded adiabatically against a constant pressure of 1 atm untill it doubl — JEE Mains Chemistry Past Papers Chemistry Question
Question
An ideal gas, V C R , is expanded adiabatically against a constant pressure of 1 atm untill it doubles in volume. If the initial temperature and pressure is 298 K and 5 atm, respectively then the final temperature is ______ K (nearest integer). [ V C is the molar heat capacity at constant volume]
Answer: .
💡 Solution & Explanation
U = q + w (q = 0) nCVT = –Pext (V2 – V1) V2 = 2V1 1 1 nRT 2nRT P P P1 = 5, T1 = 298 P2 = 5T 298 n 2 R(T2 – T1) = – 1 1 1 nRT nRT P P Put T1 = 298 and P2 = 5T 298 Solve and we get T2 = 274.16 K T2 274 K $//(1®
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