3A(g) - 2B(g) + 2C(s), first-order. P_0(A) = 6 atm, P at 20 min = 5.05 atm, P at t_inf = 4.05 atm. Correct statements:

Question

3A(g) -> 2B(g) + 2C(s), first-order. P_0(A) = 6 atm, P at 20 min = 5.05 atm, P at t_inf = 4.05 atm. Correct statements:

Prashant Kotian · Accepted Answer

Correct answer: C,D. P_0(A) = 5.85 atm, P_inert = 0.15 atm. At t=20 min: remaining P_A = 3.0 atm, so t_1/2 = 20 min exactly. (c) 93.75% = 4 half-lives = 80 min (correct). (d) After 40 min: P_A = 5.85/4 = 1.4625 atm; P_total = 5.85 - 1.4625 + 0.15 ≈ 4.55 atm (correct).

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