Total number of unpaired electrons present in the central metal atoms/ions of [Ni(CO)4], [NiCl4] 2β β JEE Mains Chemistry Past Papers Chemistry Question
Question
Total number of unpaired electrons present in the central metal atoms/ions of [Ni(CO)4], [NiCl4] 2β , [PtCl2(NH3)2], [Ni(CN4)] 2β and [Pt (CN4)] 2β is____.
Answer: .
π‘ Solution & Explanation
In [Ni(CO)4] , Ni 0 : 3d 8 4s Hybridisation state : sp Unpaired electron = 0 In [NiCl4] 2β , Ni 2+ : 3d Hybridisation state : sp Unpaired electron = 2 In [PtCl4] 2β , Pt 2+ : 5d Hybridisation state : dsp Unpaired electron = 0 In [Ni(CN)4] 2β, Ni 2+ : 3d Hybridisation state : dsp Unpaired electron = 0 In [Pt(NH3)2Cl2], Pt 2+ : 5d Hybridisation state : dsp Unpaired electron = 0
π¬Ask on WhatsApp β
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp β gets answered in minutes