Total number of unpaired electrons present in the central metal atoms/ions of [Ni(CO)4], [NiCl4] 2– — JEE Mains Chemistry Past Papers Chemistry Question
Question
Total number of unpaired electrons present in the central metal atoms/ions of [Ni(CO)4], [NiCl4] 2– , [PtCl2(NH3)2], [Ni(CN4)] 2– and [Pt (CN4)] 2– is____.
Answer: .
💡 Solution & Explanation
In [Ni(CO)4] , Ni 0 : 3d 8 4s Hybridisation state : sp Unpaired electron = 0 In [NiCl4] 2– , Ni 2+ : 3d Hybridisation state : sp Unpaired electron = 2 In [PtCl4] 2– , Pt 2+ : 5d Hybridisation state : dsp Unpaired electron = 0 In [Ni(CN)4] 2–, Ni 2+ : 3d Hybridisation state : dsp Unpaired electron = 0 In [Pt(NH3)2Cl2], Pt 2+ : 5d Hybridisation state : dsp Unpaired electron = 0
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