A sample of CaCO and MgCO weighed 2.21 g is ignited to constant weight of 1.152 g. The composition of mixture is : (Given molar mass in g mol 3 CaCO :100, MgCO :84 ) (A) 3 1.187 g CaCO 1.023g MgCO (B)

Question

A sample of CaCO and MgCO weighed 2.21 g is ignited to constant weight of 1.152 g. The composition of mixture is : (Given molar mass in g mol 3 CaCO :100, MgCO :84 )

(A) 3 1.187 g CaCO 1.023g MgCO
(B) 3 1.023g CaCO 1.023g MgCO
(C) 3 1.187 g CaCO 1.187 g MgCO
(D) 3 1.023g CaCO 1.187 g MgCO

Prashant Kotian · Accepted Answer

Correct answer: A. :-    2 CaCO s CaO s CO g       2 MgCO s MgO s CO g    Let the weight of CaCO be x gm  weight of   MgCO 2.21 x gm   Moles of CaCO decomposed = moles of CaO formed x 100  moles of CaO formed  weight of CaO formed x 100   Moles of MgCO decomposed = moles of MgO formed   2.21 x   moles of MgO formed  weight of MgO formed 2.21 x 84    2.21 x x 56 1.152 100      x 1.1886 g weight of CaCO   & weight of MgCO 1.0214 g  $//(1® Final JEE-Main Exam January, 2024/31-01-2024

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