X g of ethylamine is subjected to reaction with NaNO2/HCl followed by water; evolved dinitrogen gas — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

2 Mol.wt.45g CH CH NH NaNO HCl   H O CH3CH2–OH + 14g N given : N2 evolved is 2.24 L i.e. 0.1 mole. i.e. CH3CH2NH2 (ethyl amine) will be 4.5 g (=0.1 mole) Hence the answer = 45 × 10–1 g