0.400 g of an organic compound (X) gave 0.376 g of AgBr in Carius method for estimation of bromine. % of bromine in the compound (X) is______________. Given: Molar mass AgBr = 188 g mol–1 Br = 80 g mo

Question

0.400 g of an organic compound (X) gave 0.376 g of AgBr in Carius method for estimation of bromine. % of bromine in the compound (X) is______________. Given: Molar mass AgBr = 188 g mol–1 Br = 80 g mol–1

Prashant Kotian · Accepted Answer

Correct answer: .. Organic compound (X)     Ag AgBr 0.40 gram 0.376 gram Mole of AgBr = 188 . = 0.002 Mole of Br = 0.002 Mass of Br = 0.002 × 80 = 0.16 % of Br = . 16 . × 100 = 40%

💡 Solution & Explanation

Practice 22,000+ questions like this