The photon emitted due to electronic transition from 5th excited state to 2nd excited state in Li^2+, is used to excite He^+ already in first excited state. He^+ ion after absorbing the photon reaches

Question

The photon emitted due to electronic transition from 5th excited state to 2nd excited state in Li^2+, is used to excite He^+ already in first excited state. He^+ ion after absorbing the photon reaches in an orbit having total energy equal to:

Prashant Kotian · Accepted Answer

Correct answer: A. For Li2+, n = 6 to n = 3. For He+, the similar transition is 4 to 2. It means when electron of He+ absorbs energy at n = 2 it will go to n = 4. Energy of 4th orbit of He+ = 2 2 2

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