Match list I with List II. List – I Complex List – II CFSE (0) A. [Cu(NH3)6]2+ I. –0.6 B. [Ti(H2O)6]3– II. –2.0 C. [Fe(CN)6]3– III. –1.2 D. [NiF66]4– IV. –0.4 Choose the correct answer from the option

Question

Match list I with List II. List – I Complex List – II CFSE (0) A. [Cu(NH3)6]2+ I. –0.6 B. [Ti(H2O)6]3– II. –2.0 C. [Fe(CN)6]3– III. –1.2 D. [NiF66]4– IV. –0.4 Choose the correct answer from the options given below.

(A) A-I, B-IV, C-II, D-III
(B) A-III, B-IV, C-I, D-II
(C) A-II, B-III, C-I, D-IV
(D) A-I, B-II, C-IV, D-III

Prashant Kotian · Accepted Answer

Correct answer: A. For octahedral complex : CFSE = [– 0.4 (n) t2g + 0.6 (n) eg] 0 + *nP. Complex ion configuration ligand SFL/WFL t2g, eg configuration CFSE value [Ti(H2O)6]+3 Ti+3 d1 H2O WFL t2g1,0,0 eg0,0 –0.4 0 [Cu(NH3)6]+2 Cu+2 d9 NH3 SFL t2g2,2,2 eg2,1 –0.6 0 [Fe(Cl)6]–3 Fe+3 d5 Cl WFL t2g1,1,1 eg1,1 0 0 [NiF6]–4 Ni+2 d8 F WFL t2g2,2,2 eg1,1 –1.2 0

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