10 ml of 0.2 M solution of KxH(C2O4)y requires 8 mL of 0.2 M acidified KMnO4 solution. Then the valu — AITS & Test Series Chemistry Question
Question
10 ml of 0.2 M solution of KxH(C2O4)y requires 8 mL of 0.2 M acidified KMnO4 solution. Then the value of x is?
Answer: C
💡 Solution & Explanation
meq. of KMnO4 = meq. of KxH(C2O4)y
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