Number of moles of methane required to produce 22g CO2(g) after combustion is x × 10–2 moles. The va — JEE Mains Chemistry Past Papers Chemistry Question
Question
Number of moles of methane required to produce 22g CO2(g) after combustion is x × 10–2 moles. The value of x is
Answer: .
💡 Solution & Explanation
4(g) 2(g) 2(g) ( ) CH 2O CO 2H O CO n 0.5 moles So moles of CH4 required = 0.5 moles i.e. 50 × 10–2 mole x = 50
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes